NCERT CLASS 8TH MATHS CHAPTER 2 LINEAR EQUATIONS IN ONE VARIABLE

 CHAPTER 2

Linear Equations in One Variables







ONLINE CLASS 





Exercise 2.1



Solve the following equations and check your results.

1. 3x = 2x + 18


Subtract 2x from both sides:

3x − 2x = 18

✅ x = 18


2. 5t − 3 = 3t − 5


Subtract 3t from both sides:

2t − 3 = −5

Add 3 to both sides:

2t = −2

✅ t = −1


3. 5x + 9 = 5 + 3x


Subtract 3x from both sides:

2x + 9 = 5

Subtract 9:

2x = −4

✅ x = −2


4. 4z + 3 = 6 + 2z


Subtract 2z:

2z + 3 = 6

Subtract 3:

2z = 3

✅ z = 3/2


5. 2x − 1 = 14 − x


Add x to both sides:

3x − 1 = 14

Add 1:

3x = 15

✅ x = 5


6. 8x + 4 = 3(x − 1) + 7


Expand right side:

8x + 4 = 3x − 3 + 7

Simplify:

8x + 4 = 3x + 4

Subtract 3x and 4:

5x = 0

✅ x = 0


7. x = (4/5)(x + 10)


Expand:

x = (4/5)x + 8

Subtract (4/5)x:

(1/5)x = 8

Multiply by 5:

✅ x = 40


8. (2x/3) + 1 = (7x/15) + 3


Multiply all by 15 to clear denominators:

10x + 15 = 7x + 45

Simplify:

3x = 30

✅ x = 10


9. 2y + (5/3) = (26/3) − y


Multiply by 3:

6y + 5 = 26 − 3y

Simplify:

9y = 21

✅ y = 7/3


10. 3m = 5m − (8/5)


Subtract 5m:

−2m = −(8/5)

Divide by −2:

✅ m = 4/5

EXERCISE 2.2



Solve the following linear equations. 

1

x215=x3+14\frac{x}{2} - \frac{1}{5} = \frac{x}{3} + \frac{1}{4}

Take the LCM of denominators → 2, 3, 4, 5 → LCM = 60

Multiply through by 60:

30x12=20x+1530x - 12 = 20x + 15

Simplify:

30x20x=15+1230x - 20x = 15 + 12 10x=2710x = 27

x = 27/10 = 2.7


2.

n23n4+5n6=21\frac{n}{2} - \frac{3n}{4} + \frac{5n}{6} = 21

LCM of (2, 4, 6) = 12

Multiply by 12:

6n9n+10n=2526n - 9n + 10n = 252 7n=2527n = 252

n = 36


3.

x+78x3=1765x2x + 7 - \frac{8x}{3} = \frac{17}{6} - \frac{5x}{2}

LCM of denominators (3, 6, 2) = 6

Multiply through by 6:

6x+4216x=1715x6x + 42 - 16x = 17 - 15x

Simplify:

6x16x+15x=17426x - 16x + 15x = 17 - 42 5x=255x = -25

x = -5


4

x53=x35\frac{x - 5}{3} = \frac{x - 3}{5}

Cross multiply:

5(x5)=3(x3)5(x - 5) = 3(x - 3) 5x25=3x95x - 25 = 3x - 9 2x=162x = 16

x = 8


5

3t242t+33=23t\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t

LCM of (3, 4) = 12

Multiply by 12:

3(3t2)4(2t+3)=4(2)12t3(3t - 2) - 4(2t + 3) = 4(2) - 12t

Simplify:

9t68t12=812t9t - 6 - 8t - 12 = 8 - 12t t18=812tt - 18 = 8 - 12t t+12t=8+18t + 12t = 8 + 18 13t=2613t = 26

t = 2


6

mm12=1m23m - \frac{m - 1}{2} = 1 - \frac{m - 2}{3}

LCM of (2, 3) = 6

Multiply by 6:

6m3(m1)=62(m2)6m - 3(m - 1) = 6 - 2(m - 2)

Simplify:

6m3m+3=62m+46m - 3m + 3 = 6 - 2m + 4 3m+3=102m3m + 3 = 10 - 2m 5m=75m = 7

m = 7/5 = 1.4




Simplify and solve the following linear equations.

7

3(t3)=5(2t+1)

Expand:

3t9=10t+595=10t3t14=7t

✅ t = -2


8

15(y4)2(y9)+5(y+6)=0

Expand:

15y602y+18+5y+30=0

Simplify:

(15y2y+5y)+(60+18+30)=018y12=0

✅ y = 12/18 = 2/3


9

3(5z7)2(9z11)=4(8z13)17

Expand:

15z2118z+22=32z5217

Simplify:

3z+1=32z693z32z=69135z=70

✅ z = 2


10

0.25(4f3)=0.05(10f9)

Expand:

1f0.75=0.5f0.45

Simplify:

f0.5f=0.45+0.750.5f=0.3

✅ f = 0.6




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